These RS Aggarwal Class 6 Maths solutions are solved by expert teachers in detail to help the students in exam preparation.
Question 1. Change words into numbers or digitSolution:(i) Nine thousand eighteen = 9,018.(ii) Fifty four thousand seventy three = 54,073(iii) Three lakh two thousand five hundred six = 3,02,506.
Question 3. Expand the number.Solution:(i) 15,768 = (1 x 10000) + (5 x 1000) + (7 x 100) + (6 x 10) + (8 x 1)(ii) 3,08,927 = (3 x 100000) + (8 x 1000) + (9 x 100) +(2 x 10) +(7 x 1)
Question 4. Write the final value.Solution:-> 6 x 10000 + 2 x 1000 + 5 x 100 + 8 x 10 + 4 x 1= 60000 + 2000 + 500 + 80 + 4= 62,584.
Question 5. Find the difference between the first 9 and second 9 digit numbers.Solution:In 79520986Value of first 9 = 9000000and value of second 9 = 900Difference = 9000000 – 900= 89,99,100 Ans.
Question 6. . Find the difference between the first 7 and second 7 digit numbers.Solution:In 27650934place value of 7 = 7000000and face value of 7 = 7Difference = 7000000 – 7= 6999993 Ans.
Question 7.Solution:There are 900000 6-digits numbers in alli.e. 999999 – 99999= 900000 Ans
Question 8.Solution:There are 9999999 – 999999= 9000000 7-digits numbers in all.
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